Question

The population of a town increases 8 % annually if it's present population is 126360, what was it a year ago?​

Answer 1

Step-by-step explanation:

8%increase means if the population of the town is 100% then population increase = 108%

original population =

108/100×x=126360

x=126360×100/108

x=117000

Answer 2

Answer:

Here is a simple method my math tutor taught me, I really hope this helps you a lot!!

Step-by-step explanation:

SIMPLE CROSS MULTIPLICATION

1. So first you make the original population '100 %'. (since 100 is normally the highest per cent in math)

    x = 100 %

( x because the original population is  yet to be found)

2. Then, since it increases by 8 % you have to add 8 to 100 which is = 108

   x   =    100 %

126360 =  108  %    

*Then you cross multiply*

: 12636000 = 108x

3. Then to find x you move 108 across the equality sign to make it division or you simply divide both sides by 108 so that the x would be left alone. *simple algebra*

12636000 ÷ 108 = 117,000

4. Therefore, the population a year ago was 117,000

= 117,000