Math, asked by divyanshutiwari463, 7 months ago

The population of a town increases 8% annually . If its present population is 142560, what was it a year ago?​

Answers

Answered by skkeshriecrpdayuh
1

Answer:

Given that it increases by 8%. Its present population is 142560. = > x = 132000. Therefore, population of the town a year ago = 132000.

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Answered by AbhishekRai456696
1

Answer:

132,000

Step-by-step explanation:

Let the Population an year ago be x

According to Condition,

present population - 8% of population an year ago

= x

142560 - 8% of x = x

142560 - 8/100 * x = x

142560 - 0.08 * x = x

1.08x = 142560

x = 142560 /1.08

x = 132000

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