Question

the population of a town increases at a rate of 9% every year what was the pollution of the city 2 years ago if its present pollution is 28,00,000​

Answer 1

Answer:

2800000

Given : P=2,00,000

Population after first year

=2,00,000(1+

100

10

)

1

=2,00,000(

100

110

)=2,20,000

Principal for the second year =2,20,000

Population at the end of second year

=2,20,000[1+

100

15

=2,20,000×

100

115

Answer 2

Answer:

approx 2356700

Step-by-step explanation:

give the formula for compound interest