Question

the population of a town increases at the rate of 10 per annum if the population is 90000 in the beginning of the year 2018 what will be the population at the beginning of the year 2020 ​

Answer 1

Answer:

108900

Step-by-step explanation:

The rate of increase of population = 10%p.a

The present population of the town = 90000

Therefore the population after 1 year(2019):-

10%of 90000

= 10×90000/100

= 9000

Increase in population = 90000+9000

= 99000

Therefore, the population after 1 year is 99000

Again, the population increase by 10%p.a.

Therefore the population after 1 year (2020):-

10%of 99000

= 10×99000/100

= 9900

Increase in population = 99000+9900

= 108900

Answer 2

Step-by-step explanation:

plz mark me as branilist