Question

the population of a town increases at the rate of 50 per thousand. if the estimated population of the two year will be 22,050 find the present population of the town?

Answer 1

Population after three years = P(1+R100)n

22050 = P(1+501000)3

22050 = (1.05)2

P = 220501.1025

= 20000

Thus, the population three years ago was 20000.

Answer 2

Answer: 20,000

Step-by-step explanation:

The rate of increase population is 50 per thousand

i.e. $\dfrac{50}{1000} = 5\%$

Population after 2 years = 22050

Time = 2 years

t is time A is population after n years P is initial population

then

$A= P(1+\dfrac{R}{100} )^t\\\\\Rightarrow 22050= P(1+\dfrac{5}{100} )^2\\\\\Rightarrow 22050 = P (1+ \dfrac{1}{20} )^2\\\\\Rightarrow 22050 = P( \dfrac{21}{20} )^2\\\\\Rightarrow P = \dfrac{22050\times 20 \times 20}{21\times 21 } \\\\\Rightarrow P =20000$

Hence, the initial population is 20,000