Question

the population of a town increases by 10.5% every year. If it's present population is 795600, what was it a year ago?​

Answer 1

Answer:

> Given <

$\textsf{Population of the town increases per year = 10.5 percent}$

$\textsf{Polpulation of the town = 795600}$

> To find <

What is the population of the town after a year

> Taken <

To find population of the town after a year :

$\underline{\boxed{Pa=\frac{100+Pi}{100}×P}}$

Where,

Pa = Population after a year

Pi = Percentage of population increase per year

P = Population of the town now

> Calculation <

Population of the city after a year:

$\implies{Pa=\frac{100+10.5}{100}×795600}$

$\implies{Pa=\frac{110.5}{100}×795600}$

$\implies{Pa=110.5×7956}$

$\implies{\boxed{\color{purple}{Pa=879138}}}$

> Answer <

So , the population of the town after a year is 879138 .

> Extra information <

To find profit percent:

$Profit\:percent=\frac{Profit×100}{Cost\:price}$

To find loss percent:

$Loss\:percent=\frac{Loss×100}{Cost\:price}$

To find loss:

$Loss=Cost\:price-Selling\:price$

To find profit:

$Profit=Selling\:price-Cost\:price$