The population of a town increases by 10% annually. If the present population is 22000,find its population a year ago
Answers
Answered by
0
Answer:
22000×110/100×110/100
=26620
Answered by
0
Answer:
let present population be p
then , p= 22,000
incease in population annually = 10% = 10/100 × p = p/10
10% of p = 1/10 × 22,000 = 2,200
population a year ago = p - 10% of p
= 22,000 - 2,200
= 19,800
ans - the population of the town was 19,800 a year ago.
Step-by-step explanation:
hope it helps u
pls mark as brainliest
Similar questions
English,
6 months ago
Math,
6 months ago
Political Science,
11 months ago
Social Sciences,
11 months ago
Hindi,
1 year ago