Question

The population of a town increases by 10% annually. If the present population is 22000,find its population a year ago
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Answer 1

Answer:

22000×110/100×110/100

=26620

Answer 2

Answer:

let present population be p

then , p= 22,000

incease in population annually = 10% = 10/100 × p = p/10

10% of p = 1/10 × 22,000 = 2,200

population a year ago = p - 10% of p

                                   = 22,000 - 2,200

                                   = 19,800

ans - the population of the town was 19,800 a year ago.

Step-by-step explanation:

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