Question

The population of a town increases by 10% annually. If the present population is 22000, find the population of a year ago ​

Answer 1

Step-by-step explanation:

let the population of a year ago be x

x+x×10/100 =22000

100x+10x /100= 22000

90x/100=22000

90x =22000×100

90x =2200000

x=2200000/90

x= 24444.4444

Answer 2

Given:

Present population is 22,000

The population of the town increases 10% manually.

To find:

The population of the town a year ago.

Solution:

Population present is 22,000.

We know that,

Every year the town population increases by 10%.

Therefore, The population a year ago will be, the decrease of 10% of the population.

Therefore,

22,000 - 10%

We need to find out 10% of 22,000

22,000 * 10%

22,000 * 10/100

220 * 10

2,200

We need to subtract 2,200 from the total population,

Therefore, The population a year ago is

22,000 - 2,200

19,800

Conclusion:

Therefore, the population of the town a year ago is 19,800.