Question

the population of a town increases by 10% annually if the present population is 22000 find its population or years ago​

Answer 1

Step-by-step explanation:

Present population of town = 22000 Rate of increase in population annually = 10% Let the population 1 year ago be x. Now, (x + 10% of x) = 22000 (x + x/10) = 22000 11x/10 = 22000 x = 22000 x 10/11 X = 20000 So, The population 1 year ago will be 20000.

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Answer 2

Answer:

Hey friend here is your answer

Let the population of town 1 year ago = x

Now it is given the population of town increases by 10% annually

Present population = x+10% of x

x+10/100 * x

x + x/10

11x/10

But present population of town =22000

so, 11x/10 = 22000

11x = 220000

x = 220000/11

x = 2000

Step-by-step explanation:

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