Question

the population of a town increases by 10% annually if the present population is 22000 find its population year ago. BRAINLISTSOLVE WITH EXPLANATION I WLL GVE U THNKS AND MRK U SA BRAINLIST​

Answer 1

Answer:

increased percent=10=0.1 of the population

= 0.1×22000

=2200

now subtract this from the current population=22000-2200

=19800

Answer 2

Let the population a year ago be "x"

Given:

Present population = 22000

Increases per year = 10%

Equation:

x + (x of 10/100) = 22000

Solution:

x + (x of 10/100) = 22000

x + (x × 10/100) = 22000

x + 10x/100 = 22000

x + 10x/100 = 22000

(100x + 10x)/100 = 22000

110x/100 = 22000

110x = 2200000

x = 2200000/110

x = 20000

Therefore:

The population of the town a year ago = 20000 Ans