the population of a town increases by 10% every year.if the present population is 80000,what will be its population after 2 years.
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Answered by
0
Answer:
answer is 96000.......=...=========
Answered by
1
Answer:
First we will find the increased population of the first year and then the second. Remember that is percentage calculation every difference in number makes change.
Step-by-step explanation:
% increase in population every year = 10 %
Present population = 80,000
Increase in population in first year = 10% of 80,000
= 10/100 of 80,000
= 10 of 800
= 8000
Therefore population in first year = Present population + Increase in population in first year
= 80,000 + 8000
= 88,000
Increase in population in second year
= 10% of 88,000
=10/100 of 88,000
= 10 of 880
= 8800
Therefore population in second year = Population in first year + population increase in second year
= 88,000 + 8800
= 96,800
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