the population of a town increases by 10% every year . If the present population is 80,000, what will be it's population after 2 yrs
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Answered by
6
1st year increase in population = 80,000+ 1/10×80,000
= 80,000+8000
= 88,000
now, 2nd year increase in population = 88,000+1/10×88,000
= 88,000+8,800
= 96,800
= 80,000+8000
= 88,000
now, 2nd year increase in population = 88,000+1/10×88,000
= 88,000+8,800
= 96,800
Anonymous:
wo itna diaturb kyu kr rha tha??
Answered by
1
the answer is 96800
hope it help
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