the population of a town increases by 10 percent every year At present the population of the town is 3,63,000 what was the population of the town two years back
eshu28:
10% of 363000= 36300 .
no the answer is coming 3,00,000
363000-36300 = 326700 is the case in previous year. again 326700- 36300=290400 is the answer
No u r wrong
I hope that your method is wrong
Refer to my answer
Answers
Answered by
33
Amount=P×[1+r/100]^t
363000 = P × ( 1+10/100)^2
363000 = P × ( 1+1/10)^2
363000 = P × (10+1\10)^2[ l.c.m of denominators]
363000 = P×(11/10)^2
363000=P×(11/10×11/10)
363000=P×121/100
P=363000÷121/100
P= 363000×100/121
P=3000×100
P=300000
Therefore population before 2 years = 300000
Hope this helps
363000 = P × ( 1+10/100)^2
363000 = P × ( 1+1/10)^2
363000 = P × (10+1\10)^2[ l.c.m of denominators]
363000 = P×(11/10)^2
363000=P×(11/10×11/10)
363000=P×121/100
P=363000÷121/100
P= 363000×100/121
P=3000×100
P=300000
Therefore population before 2 years = 300000
Hope this helps
Answered by
0
Answer:
A=363000
r=10%
t = 2 years
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