the population of a town increases by 10 percentage annually. If the the persent population is 60000 what will be its population after it 2 years
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present population = 60000
after 1 year population = 60000 x 10/100 = 6000
= 66000
population in the second year = 66000 x 10/100 = 6600
= 72600
after 1 year population = 60000 x 10/100 = 6000
= 66000
population in the second year = 66000 x 10/100 = 6600
= 72600
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Population after 2years. =.
60000(1+10/100)^2. 60000(110/100)^2. 60000×12100/10000. 600×121. 72600. Ans.72600