Math, asked by surbhi1684, 1 year ago

the population of a town increases by 11% annually . if the present population is 6600000 then what will be the population after 3 years


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Answers

Answered by Anonymous
5
Hey there! here is ur solution:-

current population= 6600000
growth rate = 11%

therefore, the population of village in 3 yrs=
11% OF 6600000 = 726000

So, 726000×3= 2178000

total population will be 6600000+2178000
=8778000

*HopE* it helps :-)



surbhi1684: this is write answer i will mark you nrainlest
surbhi1684: sorry means brainlest
surbhi1684: but when I see back side the book the answer is 9026365
surbhi1684: ok
surbhi1684: but I thought that your answer is correct
surbhi1684: you can solve my another question also
Answered by Swayze
21

hy friend                              


                        here is your answer                              


    first step   ········

the present population = 6600000

rate of increase in population = 11%

=  (11/100) × 6600000

=  11 × 66000

= 726000 people per annum .

the population is increased by 726000 people per year

       now increase in population after 3 years········

=  726000 × 3

=  2178000 people


    second step      ·········

  total population after 3 years

= present population + increase in population after 3 years

= 6600000 + 2178000 people

= 8778000 people


the total population after 3 years

    is 8778000 people

                                                                                                                                 

                                    thankyou

                                   brainly user



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