the population of a town increases by 11% annually . if the present population is 6600000 then what will be the population after 3 years
surbhi1684:
please give answer
Answers
Answered by
5
Hey there! here is ur solution:-
current population= 6600000
growth rate = 11%
therefore, the population of village in 3 yrs=
11% OF 6600000 = 726000
So, 726000×3= 2178000
total population will be 6600000+2178000
=8778000
*HopE* it helps :-)
current population= 6600000
growth rate = 11%
therefore, the population of village in 3 yrs=
11% OF 6600000 = 726000
So, 726000×3= 2178000
total population will be 6600000+2178000
=8778000
*HopE* it helps :-)
Answered by
21
hy friend
here is your answer
first step ········
the present population = 6600000
rate of increase in population = 11%
= (11/100) × 6600000
= 11 × 66000
= 726000 people per annum .
the population is increased by 726000 people per year
now increase in population after 3 years········
= 726000 × 3
= 2178000 people
second step ·········
total population after 3 years
= present population + increase in population after 3 years
= 6600000 + 2178000 people
= 8778000 people
∴ the total population after 3 years
is 8778000 people
thankyou
brainly user
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