Question

The population of a town increases by 11%annually.If the present population is 6600000,then what will be the population after3years with statement

Answer 1

Total Population =6600000 11% of this population= 11/100*6600000=726000 Total Population after 1 year=6600000+726000=7326000 Population after two years =11/100*7326000+7326000=805860+7326000=8131860 Population after 3 years=11/100*8131860+8131860=894505(approx)+8131860=9026365

Answer 2

YOUR ANSWER

$- - - - - - - - - - -$

$present \: \: population = 6600000$

$increase = 11\%$

$population \: \: after \: \: 3 \: \: years$

$= 6600000 \times (1 + \frac{11}{100} ) {}^{3 }$

$= 6600000 \times ( \frac{100 + 11}{100} ) {}^{3}$

$= 6600000 \times ( \frac{111}{100} ) {}^{3}$

$= 6600000 \times \frac{111}{100} \times \frac{111}{100} \times \frac{111}{100}$

$= 9026364.6$

Hope it help you