Question

The population of a town increases by 18% annually. If the population of the town last year was 4,60,000. What will be the population in next year​

Answer 1

Answer:

640504

Step-by-step explanation:

The population of a town increases by 18% annually.  

If the population of the town last year was 4,60,000

then the population this year will be (18% of 4,60,000 + 4,60,000)

now lets find 18% of 4,60,000

=} 4,60,000 x (18/100)

=} 4600 x 18

=} 82800

now lets find the population this year

=} 4,60,000 + 82800

=} 542800

now we got the population of this year but the question asks us to find the population of next year

=} (18% of 542800 + 542800)

so lets find 18% of 542800

=} 542800 x (18/100)

=} 5428 x 18

=} 97704

now lets find the population next year

=} 542800 + 97704

=} 640504

therefore we got the population of next year

Hope it helped you

Have a good day

Answer 2

Given: The population of a town increases by 18% annually. If the population of the town last year was 4,60,000.

To find: The population in next year​.

Solution:

According to the question, the population increases by 18% annually and the population was 4,60,000 last year. In order to calculate the new population, the calculations that are shown below must be done.

$new = 460000 + (\frac{18}{100}* 460000 )$

The last year's population is multiplied to 18/100 to find 18% of the last year's population. Then, it is added to 460000 to find the total population with the increase.

$new = 460000 + 82800$

       $= 5,42,800$

This means that next year, the population would increase to 5,42,800 people.

Therefore, the population in next year​ will be 5,42,800.