the population of a town increases by 3 1/2 % of it's value at the beginning of each year.if the present population of the town is 8869743,find the population of the town three years ago. answer fast don't spam.
Answers
Answer:
The population of the town three years ago is approx 9834043.
Step-by-step explanation:
Given : The population of a town increases by 3\frac{1}{2}\%3
2
1
% of it's value at the beginning of each year. If the present population of the town is 8869743.
To find : The population of the town three years ago ?
Solution :
The population is given by,
N=N_o(1+r)^tN=N
o
(1+r)
t
The initial population is N_o=8869743N
o
=8869743
The rate is r=3\frac{1}{2}\%=\frac{7}{2}\%=0.035r=3
2
1
%=
2
7
%=0.035
The time is t=3 years
Substitute the value in the formula,
N=8869743(1+0.035)^3N=8869743(1+0.035)
3
N=8869743(1.035)^3N=8869743(1.035)
3
N=8869743\times 1.108717875N=8869743×1.108717875
N=9834042.61076N=9834042.61076
The population of the town three years ago is approx 9834043.