Question

The population of a town increases by 4% Every year. Its present population is 2,70,400. What was it 2 years ago.

Answer 1

I think it's 248768


let us assume the current population is 100% which is 270400 then 2 years ago it should be 92 % by this we can calculate the answer 248768

270400 divided by 100 and multiplied by 92


sorry my previous ans. was wrong I had done some wrong calculation but now I think it's right

Answer 2

HELLO FRIEND HERE IS YOUR ANSWER,,,,,,,,,

By applying the formula of compound interest we can make the following assumptions and calculate them for the same. You'll come across this formulae.........

Let us take it as "x" years and Total population after 2 years to find be "Y" and "PP" be present population, we'll get this ,,,

$\boxed{\bf{Y_x = PP \times [1 - \frac{r}{100}]^x}}$

Now, for population changes before "2" years ago, substitute this into "x" years ,,,

$\bf{Y_2 = 270400 \times [1 - \frac{4}{100}]^2}$

$\bf{Y_2 = 270400 \times [1 - 0.04]^2}$

$\bf{Y_2 = 270400 \times [0.96]^2}$

$\bf{Y_2 = 270400 \times [0.9216]}$

$\boxed{\bf{\therefore \: \: Y_2 = 249200.64}}$

Therefore the answer is ,,,

$\boxed{Y_2 = 2,49,200}$

HOPE THIS HELPS YOU AND CLEARS THE DOUBTS FOR CALCULATING THE TIMES OF YEAR BY THIS FORMULAE!!!!!!!