The population of a town increases by 5% annually if it is 15435 now its population 2 years ago was
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Answered by
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Hello Dear.
Here is the answer---
Given ⇒
Present Population of the Town(A) = 15435.
Rate of Increment(r%) = 5%.
Time(n) = 2 years.
Now, Using the Formula,
Present Population = Population n years ago × [1 + r/100]ⁿ
15435 = P [1 + 5/100]²
15435 = P[ 1 + 1/20]²
15435 = P[21/20]²
15435 = P [441/400]
⇒ P = 15435 × 400/441
⇒ P = 35 × 400
⇒ P = 14000
∴ Population of the town 2 years ago is 14000.
Hope it helps.
Here is the answer---
Given ⇒
Present Population of the Town(A) = 15435.
Rate of Increment(r%) = 5%.
Time(n) = 2 years.
Now, Using the Formula,
Present Population = Population n years ago × [1 + r/100]ⁿ
15435 = P [1 + 5/100]²
15435 = P[ 1 + 1/20]²
15435 = P[21/20]²
15435 = P [441/400]
⇒ P = 15435 × 400/441
⇒ P = 35 × 400
⇒ P = 14000
∴ Population of the town 2 years ago is 14000.
Hope it helps.
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