Math, asked by saurav49, 1 year ago

The population of a town increases by 5% annually. If the population is now 1,85,220, what was it an year ago

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Answered by preritmohant2004

Present Population P= 200000. After 1 year, P1 = 200000(1+0.05) = 210000. After 2 years, P2 = 210000(1-0.04) = 210000 * 0.96 = 201600. After 3 years, P3 = 201600(1+0.03) = 2016000 * 1.03 = 207648.

saurav49: not a right answer

supersonu: why

preritmohant2004: yar it is right

Answered by supersonu

Heya,

The answer is

$185220(1 - \frac{5}{100} )$
It is equal to

175959

If it helped plz mark BRAINLIEST

supersonu: check my process

supersonu: OK let's suppose the answer is 176400

supersonu: So 176400+5% of 176400 should be equal to 185220

supersonu: but it is not

supersonu: sorry u r correct somehow

saurav49: suppose an year ago population was 100, population increases every year =5%, present population = 105, if the present population is 105,then an year ago it was 100, if the present population is 1,then an year ago =100/105, if the present population is 1,85,220then an year ago it was 100/105×185220=1,76,400

saurav49: this is right answer

saurav49: hope you understand

supersonu: ya sure .. byr

supersonu: *bye

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The population of a town increases​ by 5% annually. If the population is now 1,85,220, what was it an year ago

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The population of a town increases by 5% annually. If the population is now 1,85,220, what was it an year ago