Math, asked by ArpitVirag, 8 months ago

The population of a town increases by 5% every year . If the population is 94500 now what was its population one year ago . (please any body tell ) ​

Answers

Answered by pragatifzdtiwari
4

Answer:

your answer

Step-by-step explanation:

94500(1+5/100)

94500(21/20)

89225

 or

X+5x/100=94,500

105x/100=94500

X=94500*100/105

X=90000

Answered by ammaar05
6

Answer:

90,000

Step-by-step explanation:

Increase % ➡️ 5% per year.

Present population ➡️ 94,500

Let original population = population one year ago = x

94,500 = x + 5% of x = x + 5/100 x = (1+ 1/20)x =21/20 x

➡️ x = 94,500×20/21 = 4,500×20 = 90,000

Hope this helps you.

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