The population of a town increases by 5% every year. If the population is 94,500 now, what was its population one year ago?
Answers
Given that,
- The population of a town increases by 5% every year and the population is 94,500 now.
We have to find
- The population one year ago.
So, it means we have
- Present population, A = 94500
- Increase in population, r = 5 % per annum
- Time, n = 1 year
We know,
If P is the population of the town increases every year at the rate of r % per annum for n years, then total population A is given by
So, on substituting the values, we get
Additional information :-
1. Amount received on a certain sum of money of Rs P invested at the rate of r % per annum compounded annually for n years is given by
2. Amount received on a certain sum of money of Rs P invested at the rate of r % per annum compounded semi - annually for n years is given by
3. Amount received on a certain sum of money of Rs P invested at the rate of r % per annum compounded quarterly for n years is given by
4. Amount received on a certain sum of money of Rs P invested at the rate of r % per annum compounded monthly for n years is given by
Answer:
Given :-
- The population of a town increases by 5% every year.
- The present population is 94500.
To Find :-
- What is the population after one year ago.
Formula Used :-
Amount Formula :
where,
- A = Present Population
- P = Population after year
- r = Rate of Increase
- n = Time Period
Solution :-
Given :
- Present Population = 94500
- Time Period = 1 year
- Rate of Increase = 5% every year
According to the question by using the formula we get,
By doing cross multiplication we get,
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