Question

the population of a town increases by 6% annually if the present population is 17490. what was it a year ago

Answer 1

Answer:

16800

Step-by-step explanation:

x= 1+6/100=17490

x=106/100=17490

x=17490×100/106

x=16500

Answer 2

Given:

Present population of Town = 17,490

Increase in population = 6%

To Find:

The population which was a year ago

Solution:

Let one year ago the population of town be =  x.

Therefore,

Its present population will be 106% of x

Thus, As per question -

(106/100) × x = 17490

= 106/100x = 17490

= 53/50x = 17490

x = 17490 × 50/53

x = 330 × 50

x = 16500

Answer: The population of the town a year ago was 16500.