Question

the population of a town increases by 6% annually the present population is 17 4890 what was it a year ago?​

Answer 1

Answer:

Step-by-step explanation:

the population of a town increase by 6% annually.

the present population is 17490.

let one year ago the population of town be x.

so now we found the value of x.

X ×(1+6/100) Ka power 1 = 17490

X ×(106/100) = 17490

=X × 106/100 = 17490

=X = 17490×100/106

= X = 16500

Answer 2

Step-by-step explanation:

precent population=174890

increasing rate=4%

let ,

the population 1 year ago=x

Aq.

106% of x=174890

106/100×x=174890

x =174890×100/106

x. 164990.56