Question

the population of a town increases by 6 percent anually. if it is 53,000 in the year 2010. what was its population in 2009​

Answer 1

Answer:

Let the population in 2006 be x.

Pop. in 2009=x

$\huge{(1+ \frac{5}{100} )3}$

⇒1,38,915=x

$\huge{( \frac{21}{20})}$

⇒x= 138915×8000 =120000

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