Question

The population of a town increases by
8% annally the present population
es 5400, what was' it a year ago,​

Answer 1

Answer: 4,968

Step-by-step explanation:

Let total population = 100%

Increase in population annually = 8%

⇒ Population a year ago = (100 - 8)% = 92%

⇒ Population in numbers

= 92% of 5400

$=\frac{92}{100} *5400$

$=92*54$

$=4,968$

Hope it helps.

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