Question

the population of a town increases by 8%annually. if the percent population is 54000,what was it a year ago?​

Answer 1

Answer:

50000

Step-by-step explanation:

Let the population of 1 years ago was x

So,present population is =x+x×8%=108x/100

So,108x/100=54000

Thus,x=50000

Answer 2

Answer:

50000

Step-by-step explanation:

Let the population an year ago be x

It given in the question that it increases 8% annually

Present population = 54000

A.T.Q

Population an year ago + 8% of that population =Present population

x + 8% of x = 54000

x + 8/100x = 54000

By taking the L.C.M

(100x + 8x)/100 = 54000

108x/100 = 54000

x = (54000×100)/108

x = 50000

Therefore population an year ago was 50000