Question

The population of a town increases every years by 4% if the present population is 50000, what was the population of the town 3
ago?​

Answer 1

Present Population - 50,000 (P)

Every year percentage increase - 4% (R)

Time - 3yrs (N)

$\color{purple}\huge{Compound\: Interest :-} \\ \\ Amount = P(\frac{R}{100} + 1)^{N} \\ \\ A = 5000(\frac{4}{100} + 100/100)^{3} \\ \\ A = 5000(\frac{104}{100})^{3} \\ \\ 50000 \times \frac{104}{100}\times \frac{104}{100} \times \frac{104}{100} = 56,243.2 \\ \\ \bold\color{red}{Hence \: after\: 3 \:yrs \:the\: population\:will\: be\: 56,243.2}$

Answer 2

Answer:

44,236.8 population 3 years ago

Step-by-step explanation:

Sol:-

•       Given that present population is 50,000.

•       And each year the population is increased by 4%

           So,

•      Before 1 year, the population would  be = 50,000 - 4% of 50,000

                                                                                 = 50,000 - 4/100 x 50,000

                                                                                 = 50,000 - 4 x 500

                                                                                 = 50,000 - 2000

                                                                                 = 48,000.

• Before 2year, the population would be = 48,000 - 4/100 x 48,000

                                                                          = 48,000 - 1920

                                                                          = 46,080.

• Before 3 years, The population would be = 46,080 - 4/100 x 46080

                                                                              = 46080 - 1/25 x 46080

                                                                              = 46080 - 1843.2

                                                                               = 44,236.8