Math, asked by venkatakrishnan12438, 1 year ago

the population of a town increases from 180000 to 225000 in a year find the percentage increase in the population of the town

Answers

Answered by AdityaEswar
21

Increase value=225000-180000=45000.
percentage increase=increase in value divided by original value multiply with 100 .180000 divided by 45000 multiplied by 100 then the increase value percentage is 25 percent

venkatakrishnan12438: how the 25 is came
AdityaEswar: 180000 two zero will be cancelled then 45000 divided by 1800 it will come 25
Answered by Agastya0606
1

Given:

The population of a town increased from 180000 to 225000 in a year.

To find:

% increase in population.

Solution:

The % increase in population is 25℅.

To answer this question, we will follow the following steps:

As given in the question, we have,

The initial population of a town = 180000

In a year, the population of town increases by = 225000

So,

The increase in population

= population increased in a year - initial population

= 225000 - 180000

= 45000

So,

The percentage increase in population in a year

= \frac{population \: increase}{initial \:population } \times 100

 =  \frac{45000}{180000}  \times 100

 = 25

Hence, the percentage increase in population is 25%.

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