the population of a town increases up to 10%every year .if the present population is 14000.find the population after 2 years
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Answered by
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Here is your answer :-
Present population of town = 14000
Rate of increase in population annually = 10%
Let the population 1 year ago be x .
Now,
(x + 10% of x) = 14000
(x + x/10) = 14000
11x/10 = 14000
x = 14000 × 10/11
x = 12000
So,
The population 1 year ago will be 12000.
Hope my answer will be helpful to you.
Answered by
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here is your answer............
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