Question

the population of a town increses by 10% every year if the population is 60500 find the population after 2 years and two years ago​

Answer 1

population=60500r%=10%t=2yrspopulationafter2years=p(1+100r​)n=60500(1+10010​)2=60500×100110​×100110​=73205​

Answer 2

$population = 60500 \\ r\% = 10\% \\ t = 2yrs \\ population \: after \: 2 \: years = p(1 + \frac{r}{100} {)}^{n} \\ = 60500 (1 + \frac{10}{100} {)}^{2} \\ = 60500 \times \frac{110}{100} \times \frac{110}{100} \\ = 73205$

population 2 years ago=p(1-r/100)^n
=60500(1-10/100)^2
=60500×90/100×90/100
=49005

please mark it as a brainliest