Question

The population of a town is 1,20,000 and it increases at the rate of 10% p.a. find the population of the town after 3 years​

Answer 1

Answer:

The present population of a town is 2,00,000 . Its population increases by 10

Answer 2

Given:

A town with

• Population = 1,20,000
• Rate = 10%
• Time = 3 years

What To Find:

We have to find the population after 3 years​.

How To Find:

To find the population after 3 years​, we will use the formula of CI (Compound Interest),

$\sf{A = P \bigg(1 + \dfrac{R}{100} \bigg) ^T}$

Where

• A = Amount (Population after 3 years)
• P = Principal (Population now)
• R = Rate
• T = Time

Solution:

Using the formula,

⇒ $\sf{A = P \bigg(1 + \dfrac{R}{100} \bigg) ^T}$

Substitute the value,

⇒ $\sf{A = 1,20,000 \bigg(1 + \dfrac{10}{100} \bigg) ^3}$

Solve the brackets,

⇒ $\sf{A = 1,20,000 \bigg( \dfrac{110}{100} \bigg) ^3}$

Remove the brackets,

⇒ $\sf{A = 1,20,000 \times \dfrac{110}{100} \times \dfrac{110}{100}\times \dfrac{110}{100}}$

Cancel the zeros,

⇒ $\sf{A = 12 \times 11 \times 11 \times 110}$

Multiply the numbers,

⇒ A = 1,59,720

∴ Thus, the population of the town after 3 years will be 1,59,720.