Question

The population of a town is 10,000 with the number of males and that of females in the ratio of 3:2. If the number of males increases by 20% and the number
of females decreases by 20%, what will be the ratio of the number of males and to that of females?​

Answer 1

Let the ratio be x.
No. Of male= 3x
No. Of females= 2x
ATQ
3x+2x=10000(town population)
5x=10000
X= 10000/5= 2000
Thus, present no. Of males= 3*2000= 6000
Present no. Of women= 2*2000= 4000

Increase in male population= 20%= 20/100*6000= 1200
Decrease in female population= 20%= 20/100*4000= 800
Atq
New ratio= 6000+1200/4000-800= 7200/3200= 36/16= 18/8=9/4
=> 9:4