Question

the population of a town is 10000 in a certain year . if the rate of growth is 8 % per annum then find the total population after two years anf also gind the net increase in population.​

Answer 1

Answer:

The present population was 11130

Step-by-step explanation:

We are given that two years ago the population of the town was 10000

During first year it increased at the rate of 5% per annum

So, Population after 1st year =  

During second year it increased at the rate of 6% per annum

So, Population after 2nd year =  

So, Present population = 11130

Hence the present population was 11130

#Learn more:

The present population of a town is 176400. If the rate of growth in its population is 5%per

annum, find : (i) its population 2 years hence, (i) its population one year ago​

Answer 2

Given: Rate of growth is $8%$%. and population of town is 10,000

Find: The total population after two years  and also find the net increase in population.

Now, The rate of growth is $8$% annum.

So, the growth is $108$%.

Now,

Population after two years

$=10000\times\frac{108}{100} \times\frac{108}{100} \\=11664$

Net increase in population $=\frac{final - initial}{inital} \times 100\\=\frac{11664-10000}{10000} \times100\\=16.64%$

So, the net increase in population is$16.64$%