Math, asked by hilekhesh20, 1 month ago

The population of a town is 175000. The number of women are 66% of number of men. If the number of men increased by 15%
and the number of women increased by 10%, what is the percentage change in the population of town?​

Answers

Answered by gyaneshwarsingh882
0

Answer:

For example

Step-by-step explanation:

GIVEN :

The population of a town = 7500

The number of males increases by 10%  

The number of females increases by 25%  

After increment in male and female the population of the town = 9000

 

ASSUMPTION :

Let the male population of the town be x  

So, the female population of the town = 7500 – x  

 

CALCULATION :

After increment, the number of male = x × 110/100 = 11x/10

After increment, the number of female = (7500 – x) × 125/100

⇒ 5(7500 – x)/4

⇒ (37500 – 5x)/4

⇒ 11x/10 + (37500 – 5x)/4 = 9000

= (22x + 187500 – 25x)/20 = 9000

⇒ 187500 – 3x = 180000

⇒ 3x = 7500

⇒ x = 2500

∴ The male population of the town is 2500

Alternative Method

Previously population was 7500

Present population 9000

⇒ Overall population increased (90000 - 75000) = 1500

⇒ Overall population increase % = (1500/7500) × 100 = 20%

Male increased by 10% and female increased by 25%

Applying Alligation method get,

          Male                                            Female

            10%                                               25%

                                     20%

 

     (25 - 20) = 5%                              (20 - 10) = 10%

Male : Female = 5 : 10 = 1 : 2

Initially number of male in the town was (1/3) × 7500 = 2500

∴ Number of male in the town was 2500.

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