Math, asked by samhithapoladi, 10 months ago

The population of a town is 176400. It increases annually at the rate of 5% per annum. What will be its population after 2 years? What was it 2 years ago?

Answers

Answered by ddvv0808
1

Answer:

Total population in 2 years is 194481.

Total population 2 years ago is 160000.

Step-by-step explanation:

Given : Population of a town is 176400. If it increases at the rate of 5% per annum.

To find : What will be its population 2 years hence?

What was it 2 years ago ?

Solution :

Let P be the population, P=176400

r is the increasing rate, r=5%

t is the time (in years) t=2

It is form by an exponential function represented as

A=P(1+\frac{r}{100})^t

A=176400(1+\frac{5}{100})^2

A=176400(1.1025)

A=194481

Total population in 2 years is 194481

Two years ago the population is,

A=P(1+\frac{r}{100})^t

176400=P(1+\frac{5}{100})^2

176400=P(1.1025)

P=\frac{176400}{1.1025}

P=160000

Total population 2 years ago is 160000.

Answered by arpitkatiyar1999
2

Answer:

176400×(105/100)×(105/100)

so after 2 year populatiowill be

=194481

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