the population of a town is 200000 it increases anually at the rate of 10%. what will be the population after 2 years?
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Answer:
The present population is, 200,000
Rate of increase per year is 2%
Hence the population after one year will be = 200000 *102/100= 204000
Population after the second year = 204000 *102/100 = 208080
Step-by-step explanation:
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Step-by-step explanation:
amount=p(1+r/100)
amount =200000(1+10/100)²
a= 200000(110/100)²
a= 200000(11/10)²
a=200000×11/10×11/10
a=242000
population = 242000
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