The population of a town is 50,000 if annual emigration rate is 6% and the annual immigration rate is 4% calculate the population after two years
Answers
Answered by
9
Hello mate!!
6% of 50,000 is 3000
4% of 50,000 is 2000
Emigration means they are leaving the town. So -3000
Immigration means they are coming in. So +2000
-3000+2000= -1000
After first year the total is 49000
6% of 49000 is 2940
4% of 49000 is 1960
-2940+1960= -980
So 49000-980= 48020.
Hope it helpful
6% of 50,000 is 3000
4% of 50,000 is 2000
Emigration means they are leaving the town. So -3000
Immigration means they are coming in. So +2000
-3000+2000= -1000
After first year the total is 49000
6% of 49000 is 2940
4% of 49000 is 1960
-2940+1960= -980
So 49000-980= 48020.
Hope it helpful
abeinstein:
But ans is 48000
Answered by
6
Answer:
Step-by-step explanation:
population of the town = 50000
annual emigration = 6%
annual immigration = 4%
annual emigration = 50000*6/100= 3000
annual immigration = 50000*4/100=2000
the population reduces from 50000 to 49000 in a year
the population reduces to 48000 in two years
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