Question

The population of a town is 5000. If the males increases by 6 percent and females by 14 percent the population will be 5500. Find the number of females in the town.

Answer 1

Answer:

Total inc = 500 = 10% of total ,

use alligation now to avoid calculation.

6 14

10

4 4

1:1

so, male and female both are = 2500 each .

$\color{red}{Mark\: as\: Brainlist}$

Answer 2

Answer:

The number of females in the town are 2500.

Step-by-step explanation:

Given :

• The population of a town is 5000.

• The population of males increases by 6 percent.

• The population of females increases by 14 percent.

To find : The number of females in the town.

Solution:

Let the number of male and female be x and y respectively.

According to the first condition,

x + y = 5000     ................................(1)

Now,

The population of males increases by 6 percent, i.e.,

          new male population = x + x*6% = x + 0.06x  =  1.06x

The population of females increases by 14 percent, i.e.,

          new female population = y + y*14% = y + 0.14y  =  1.14y

So, 1.06x + 1.14y = 5500            ............................... (2)

Then, multiplying equation (1) by 1.06 and subtracting it from equation (2), we get:

⇒ 1.14y - 1.06 y = 5500 - 5000*1.06

⇒ 0.08 y = 5500 - 5300  ⇒  0.08 y = 200  ⇒  y  =  2500

Thus, the number of females in the town are 2500.

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