Math, asked by hkumarrai456, 6 months ago


The population of a town is 6,00,000. If birth rate is 7.5% p.a. and the death rate is 4.5% p.a.
Find the population of town after 1 and half year​

Answers

Answered by raginikri2007
3

Answer:

Annual birth rate is 4%

Annual death rate is 2%

Net =+2%

Population after 2 years =(1+0.02)

2

×20000=20808

Answered by SANDHIVA1974
2

Answer:

✴ Given :-

➬ Population of town = 600000

➬ Birth rate = 7.5 %

➬ Death rate = 4.5 %

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

✴ To Find :-

➬ Population after 1 × 1/2 years .

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

✴ Solution :-

❒ Formula Applied :

\large{\blue{\bigstar}}{\underline{\boxed{\red{\sf{P_{1.5\: years} = P\bigg(1 + \dfrac{R}{N} \bigg)^ {n \times t}}}}}}

Here :

➳ P_1.5 = ?

➳ Interest rate = R = 0.03 %

➳ Time = 18 months or 1.5 years

➳ n = 12 months

➳ Compounded = Monthly

\qquad{━━━━━━━━━━━━━━━━━━━━━━━}

❒ Finding the Population :

\qquad{\dashrightarrow{\qquad{\sf{P_1.5 = P\bigg(1 + \dfrac{R}{N} \bigg)^ {n \times t}}}}}

\qquad{\dashrightarrow{\qquad{\sf{P_{1.5} = 600000\bigg(1 + \dfrac{0.03}{12} \bigg)^ {12 \times 1.5}}}}}

\qquad{\dashrightarrow{\qquad{\sf{P_{1.5} = 600000\bigg(1 + {1.0025} \bigg)^ {18}}}}}

\qquad{\dashrightarrow{\qquad{\sf{P_{1.5} = 600000 ×1.046 }}}}

\qquad{\qquad{\large{\red{:\longmapsto{\underline{\overline{\boxed{\green{\sf{ 627600}}}}}}}}}}

\qquad{━━━━━━━━━━━━━━━━━━━━━━━}

❒ Therefore :

❝ Population after 1 × 1/2 years is 627600 .❞

{\pink{\underline{▬▬▬▬▬}}}{\color{darkblue}{\underline{▬▬▬▬▬}}}{\orange{\underline{▬▬▬▬▬}}}{\red{\underline{▬▬▬▬▬▬}}}

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