- The population of a town is 6,00,000. If birth rate is 7.5% p.a. and the death rate is 4.5% p.a.
Find the population of town after 1 ×1/2
please answer
Answers
Answered by
80
Answer: ≈ 6,276,00
Given that:
- Birth rate, b = 7.5/100 = 0.075 p.a
- Death rate, d = 4.5/100 = 0.045 p.a
- Current population, p = 6,00,000
We converted birth and death rate percentage into rate by dividing it by 100.
To Find:
- Population after 1 × 1/2 years or 1 year 6 months.
Solution:
We can solve it by applying the concept of Compound Interest. So, we have
- Principal value, p = 6,00,000
- Interest rate, r = b - d = 0.075 - 0.045 = 0.03
- Time, t = 18 months or 1.5 years
- n = 12 times per year or Compounded monthly
Now,
=> p" = p(1 + r/n)^(nt)
=> p" = 6,00,000 ( 1 + 0.03/12 )^(12×1.5)
=> p" = 6,00,000 (1.0025)^(18)
=> p" ≈ 6,00,000 × 1.046
=> p" ≈ 6,27,600
Hence, The population after one and a half year will be approx. 6,27,600.
Answered by
98
✴ Given :-
- ➬ Population of town = 600000
- ➬ Birth rate = 7.5 %
- ➬ Death rate = 4.5 %
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
✴ To Find :-
- ➬ Population after 1 × 1/2 years .
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
✴ Solution :-
❒ Formula Applied :
Here :
- ➳ P_1.5 = ?
- ➳ Interest rate = R = 0.03 %
- ➳ Time = 18 months or 1.5 years
- ➳ n = 12 months
- ➳ Compounded = Monthly
❒ Finding the Population :
❒ Therefore :
❝ Population after 1 × 1/2 years is 627600 .❞
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