Question

The population of a town is 6000. If males are increased by 5 % and female are increased by 9%. then population will become 6500 after 3 year. Find the no of males & females.​

Answer 1

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The population of the town = 6000

Let no. of males be “M” and no. of females be “F”.

Thus,

M + F = 6000

⇒ F = 6000 – M …….. (i)

Now, M increases by 5% and F increases by 9% and the population after the increase becomes 6500. Thus, we can write

1.05M + 1.09F = 6500

Putting the eq. (i), we get

⇒ 1.05 M + 1.09(6000 – M) = 6500

⇒ 1.05 M + 6540 – 1.09 M = 6500

⇒ 0.04 M = 40

⇒ M = 40 / 0.04 = 1000

Hence, the no. of males in the town is 1000.

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