The population of a town is 6000. If the males increase by 5% and the females by 9%, the population will be 6500. Find the number of males in the town
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Answer:
The population of the town = 6000
Let no. of males be “M” and no. of females be “F”.
Thus,
M + F = 6000
⇒ F = 6000 – M …….. (i)
Now, M increases by 5% and F increases by 9% and the population after the increase becomes 6500. Thus, we can write
1.05M + 1.09F = 6500
Putting the eq. (i), we get
⇒ 1.05 M + 1.09(6000 – M) = 6500
⇒ 1.05 M + 6540 – 1.09 M = 6500
⇒ 0.04 M = 40
⇒ M = 40 / 0.04 = 1000
Hence, the no. of males in the town is 1000.
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The population of a town is 5000.if the males increase by 6% and the females by 14%, the population will be 5500.find the number of females in the town
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