The population of a town is
6000o, in 2014 what was
the populatim in 2011. if
it increased by 6% per annum
Answers
Answered by
1
Step-by-step explanation:
Population of the town =60,000.
Rate of increase for the first year (p)=5%
Rate of increase for the second year (q)=4%
Rate of increase for the third year (r)=3%
Time =3 years
Now,
Present population =P×(1+
100
p
)×(1+
100
q
)×(1+
100
r
)
=60000×(1+
100
4
)×(1+
100
5
)×(1+
100
6
)
=60000×
100
104
×
100
105
×
100
106
=6×21×26×21.2=69451.2
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0
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