Math, asked by dhirajkumarjsr9900, 6 months ago

The population of a town is
6000o, in 2014 what was
the populatim in 2011. if
it increased by 6% per annum​

Answers

Answered by nikilanarul
1

Step-by-step explanation:

Population of the town =60,000.

Rate of increase for the first year (p)=5%

Rate of increase for the second year (q)=4%

Rate of increase for the third year (r)=3%

Time =3 years

Now,

Present population =P×(1+

100

p

)×(1+

100

q

)×(1+

100

r

)

=60000×(1+

100

4

)×(1+

100

5

)×(1+

100

6

)

=60000×

100

104

×

100

105

×

100

106

=6×21×26×21.2=69451.2

Answered by vidyasagaradv14
0

Answer:

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