The population of a town is 64000. if the annual birth rate is 10.7percent and the annual death rate is 3.2percent calculate the population after three years
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Answered by
9
net growth rate=birth-death=10.7-3.2=7.5%
A=p(1r/100)^t
A/population= 64000(107.5/100)^3
A=64000*12,42,296.875/1000000
A=79507
the population will be 79507
A=p(1r/100)^t
A/population= 64000(107.5/100)^3
A=64000*12,42,296.875/1000000
A=79507
the population will be 79507
Answered by
4
(64000*0.107)+64000. birth rate
6848+64000=70848
70848-(70848*0.032) death rate
70848-2267.136
68580 (approx)
this is the population after 1 year
the population after 3 years=3(68580)
=205740
so, the population after 3 years is 205,740.
6848+64000=70848
70848-(70848*0.032) death rate
70848-2267.136
68580 (approx)
this is the population after 1 year
the population after 3 years=3(68580)
=205740
so, the population after 3 years is 205,740.
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