Question

The population of a town is 64000.if the annual birthrate is 10.7% and the annual death rate is 3.2.calculate the population after 3 years.

Answer 1

birth rate = 10.7%
death rate = 3.2%
rate of increase in population = birth rate - death rate = 10.7-3.2 = 7.5%

the population 64000
then increase in population in 1st year = (7.5/100)*64000= 4800
population at the end of first year = 64000+4800 = 68800

then increase in population in 2nd year = (7.5/100)*68800= 5160
population at the end of second year = 68800+5160 = 73960

then increase in population in 3rd year = (7.5/100)*73960= 5547
population at the end of third year = 73960+5547 = 79507

So the population at the end of third year is 79507.

Answer 2

Answer:

Step-by-step explanation:

birth rate = 10.7%

death rate = 3.2%

rate of increase in population = birth rate - death rate = 10.7-3.2 = 7.5%

the population 64000

then increase in population in 1st year = (7.5/100)*64000= 4800

population at the end of first year = 64000+4800 = 68800

then increase in population in 2nd year = (7.5/100)*68800= 5160

population at the end of second year = 68800+5160 = 73960

then increase in population in 3rd year = (7.5/100)*73960= 5547

population at the end of third year = 73960+5547 = 79507