The population of a town is 80,000 . If the population increases annually at the rate of 75 per 1000 , find the population of this town after 2 years .
Answer:- 92,450
Answers
Answer:
the population of a town is 80,000
after 1 year population increase
80,000×75/1000=6000
after 1 year population will be(80,000+6000)
=86,000
after 2nd year population increase
86,000×75/1000
=6450
so, after 2 years population will be
(86,000+6450)
=92,450
The population of the town after 2 years is 92,450.
Given:
The population of the town is 80,000. The population increases annually at the rate of 75 per 1000
To find:
Find the population of this town after 2 years.
Solution:
The population of the town is 80,000.
The rate of increase = 75 per 1000
The population of town after 1 year
= [ 75/1000] × 80,000 + 80,000
= 0.075 × 80,000 + 80,000
= 6000 + 80,000
= 86000
After 1 year the population = 86000
Now calculate the population in 2nd year as follows
The population of town after 2 year
= [ 75/1000] × 86000 + 86000
= 0.075 × 86000 + 86000
= 6450 + 86000
= 92450
Therefore,
The population of the town after 2 years is 92,450.
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