Question

The population of a town is 800000. It is increasing at the rate of 4% per annum. What will be its population after 2 years.​

Answer 1

Answer:

Let the population of the town after 2 years be x

Increase percent of population every year = 10%

Present population = 180000

= 10% of 180000

= 10/100 * 180000 = 10*1800 = 18000

Increase in population after 1 year = 180000+18000 = 198000

Increase in population afer 2 years = 10% of population in 1 year + population of 1 year

= 10% of 198000+198000

= 10/100 * 198000 = 10*1980 = 19800

= 198000+19800 = 217800

Therefore, the population of the town after 2 years is 2,17,800.

Answer 2

Answer:

Let the population of the town after 2 years be x

Increase percent of population every year = 10%

Present population = 180000

= 10% of 180000

= 10/100 * 180000 = 10*1800 = 18000

Increase in population after 1 year = 180000+18000 = 198000

Increase in population afer 2 years = 10% of population in 1 year + population of 1 year

= 10% of 198000+198000

= 10/100 * 198000 = 10*1980 = 19800

= 198000+19800 = 217800

Therefore, the population of the town after 2 years is 2,17,800.