Question

the population of a town is increased by 6% annually if its 53000 in the year 2018 , what was its population in 2017?​

Answer 1

Answer:

50000

Step-by-step explanation:

Let,the population in 2017 id P

P×(1+6/100)¹ = 53000

P= 53000×100/106

P= 50000

Answer 2

Answer:

Let the population of town in a year 2017 be a.

Then its population in the year 2018 = 106% of a which is given as 53000.

Thus, 106/ 100 × a = 53000

i.e. 53a/50 = 53000

a = 53000×50/ 53

a= 2,650,000/ 53

a = 50,000

Hence, the population of the town in 2017 was 50,000.